-4.9x^2+3500=0

Solution for -4.9x^2+3500=0 equation:

-4.9x^2+3500=0

a = -4.9; b = 0; c = +3500;
Δ = b2-4ac
Δ = 02-4·(-4.9)·3500
Δ = 68600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{68600}=\sqrt{4900*14}=\sqrt{4900}*\sqrt{14}=70\sqrt{14}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-70\sqrt{14}}{2*-4.9}=\frac{0-70\sqrt{14}}{-9.8}
=-\frac{70\sqrt{14}}{-9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+70\sqrt{14}}{2*-4.9}=\frac{0+70\sqrt{14}}{-9.8}
=\frac{70\sqrt{14}}{-9.8}
$